opencv copy mat

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opencv copy mat*******cv::Mat source = cv::imread("basic_shapes.png"); cv::Mat dst = source.clone(); This will do the trick. You are making an image with one channel only . I need to copy a cv::Mat image (source) to an ROI of another (Destination) cv::Mat image. I found this reference, but it seems that it does not work for my case. Do . cv::Mat CopyOneImage(const cv::Mat& orgImage) { cv::Mat image; orgImage.copyTo(image); return image; } int main() { std::string orgImgName("a.jpg"); . Mat::copyTo is for when you already have a destination cv::Mat that (may be or) is already allocated with the right data size. Mat::clone is a convenience for when you . I can't figure how to copy a part of mat to another mat. ( or to itself) I want for example to copy (or to keep) only the first row of srcMat. I am using : for ( int x = 0; x .The Mat::clone() method can be used to get a full (deep) copy of the array when you need it. Construct a header for a part of another array. It can be a single row, single column, .

Whenever somebody copies a header of a Mat object, a counter is increased for the matrix. Whenever a header is cleaned, this counter is decreased. When the counter reaches zero the matrix is .opencv mat access element A Mat keeps a reference count that tells if data has to be deallocated when a particular instance of Mat is destroyed. Here is an example of creating two matrices . Need description of the following code : 1 Mat A = imread(argv[1], CV_LOAD_IMAGE_COLOR); 2 Mat F = A.clone(); 3 Mat G; 4 A.copyTo(G); The second .

If it is desired to actually copy an array's data into an OpenCV Mat object thus giving it it's own separately allocated data to work with you can utilize the memcpy function from the C++ standard library. For example, below I construct a Mat object with 11 rows and columns and of type CV_8U. cv::Mat source = cv::imread("basic_shapes.png"); cv::Mat dst = source.clone(); This will do the trick. You are making an image with one channel only (which means only shades of gray are possible) with CV_8UC1 , you could use CV_8UC3 or CV_8UC4 but for simply copying stick with the clone function. cv::Mat CopyOneImage(const cv::Mat& orgImage) { cv::Mat image; orgImage.copyTo(image); return image; } int main() { std::string orgImgName("a.jpg"); cv::Mat orgImage; orgImage = cv::imread(orgImgName); cv::Mat aCopy; aCopy = CopyOneImage(orgImage); return 1; } But why? It's not a deep copy.opencv copy mat opencv mat access element I need to copy a cv::Mat image (source) to an ROI of another (Destination) cv::Mat image. I found this reference, but it seems that it does not work for my case. Do you have any pointers how could I do this using the OpenCV C++ interface?

The Mat::clone() method can be used to get a full (deep) copy of the array when you need it. Construct a header for a part of another array. It can be a single row, single column, several rows, several columns, rectangular region in the array (called a . Whenever somebody copies a header of a Mat object, a counter is increased for the matrix. Whenever a header is cleaned, this counter is decreased. When the counter reaches zero the matrix is freed. Sometimes you will want to copy the matrix itself too, so OpenCV provides cv::Mat::clone() and cv::Mat::copyTo() functions. A Mat keeps a reference count that tells if data has to be deallocated when a particular instance of Mat is destroyed. Here is an example of creating two matrices without copying data ( C++ only ): std::vector points; If it is desired to actually copy an array's data into an OpenCV Mat object thus giving it it's own separately allocated data to work with you can utilize the memcpy function from the C++ standard library. For example, below I construct a Mat object with 11 rows and columns and of type CV_8U.

Is there a possibility, to copy a mat at a pixels bounded by a specific contour (not it´s boundRect!) resp. a binary Mask into another mat? Thanks for helping. Mat::copyTo is for when you already have a destination cv::Mat that (may be or) is already allocated with the right data size. Mat::clone is a convenience for when you know you have to allocate a new cv::Mat.opencv copy mat I can't figure how to copy a part of mat to another mat. ( or to itself) I want for example to copy (or to keep) only the first row of srcMat. I am using : for ( int x = 0; x < height; x++ ) { for ( int y = 0; y < width; y++ ) {. cv::Mat source = cv::imread("basic_shapes.png"); cv::Mat dst = source.clone(); This will do the trick. You are making an image with one channel only (which means only shades of gray are possible) with CV_8UC1 , you could use CV_8UC3 or CV_8UC4 but for simply copying stick with the clone function. cv::Mat CopyOneImage(const cv::Mat& orgImage) { cv::Mat image; orgImage.copyTo(image); return image; } int main() { std::string orgImgName("a.jpg"); cv::Mat orgImage; orgImage = cv::imread(orgImgName); cv::Mat aCopy; aCopy = CopyOneImage(orgImage); return 1; } But why? It's not a deep copy. I need to copy a cv::Mat image (source) to an ROI of another (Destination) cv::Mat image. I found this reference, but it seems that it does not work for my case. Do you have any pointers how could I do this using the OpenCV C++ interface?The Mat::clone() method can be used to get a full (deep) copy of the array when you need it. Construct a header for a part of another array. It can be a single row, single column, several rows, several columns, rectangular region in the array (called a .

Whenever somebody copies a header of a Mat object, a counter is increased for the matrix. Whenever a header is cleaned, this counter is decreased. When the counter reaches zero the matrix is freed. Sometimes you will want to copy the matrix itself too, so OpenCV provides cv::Mat::clone() and cv::Mat::copyTo() functions. A Mat keeps a reference count that tells if data has to be deallocated when a particular instance of Mat is destroyed. Here is an example of creating two matrices without copying data ( C++ only ): std::vector points;

If it is desired to actually copy an array's data into an OpenCV Mat object thus giving it it's own separately allocated data to work with you can utilize the memcpy function from the C++ standard library. For example, below I construct a Mat object with 11 rows and columns and of type CV_8U.

Is there a possibility, to copy a mat at a pixels bounded by a specific contour (not it´s boundRect!) resp. a binary Mask into another mat? Thanks for helping.

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opencv copy mat|opencv mat access element